| T O P I C R E V I E W |
| azdroppy |
Posted - Apr 20 2016 : 8:13:56 PM
'Create implementation'
If I have such class (being templated is vital).
namespace a
{
template<typename data_t>
class b
{
public:
void foo();
template<typename src_t>
void makeFoo(src_t&&);
};
}
And then 'Create implementation' for foo() then I get:
namespace a
{
template<typename data_t>
class b
{
public:
void foo();
template<typename src_t>
void makeFoo(src_t&&);
};
template<typename data_t>
void a::b<data_t>::foo()
{
}
}
where 'a::' after void is surplus and I have to delete it manuall to make code look good.
If I 'create implementation' for makeFoo then the created method looks:
template<typename src_t>
void a::b::makeFoo(src_t&&)
{
}
It has only 'inner' template definition of the method and misses 'external' class template.
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| 1 L A T E S T R E P L I E S (Newest First) |
| feline |
Posted - Apr 21 2016 : 12:41:51 PM
Thank you for the clear code, I am seeing the same effects here.
For the "foo" function, with the namespace being added, this is a known bug:
case=4240
Since this code still compiles, this is not a high priority bug, but I agree, it does not look as nice as it could, and this is a bug.
For the "makeFoo" template function, this is also a known bug, and it is one we are hoping to get to fairly soon:
case=5476
Unfortunately I don't currently have an estimate, but since this is generating invalid code it is clearly important. |
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