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azdroppy
New Member

Cyprus
8 Posts

Posted - Apr 20 2016 : 8:13:56 PM

'Create implementation'

If I have such class (being templated is vital).

namespace a
{
template<typename data_t>
class b
{
public:
void foo();
template<typename src_t>
void makeFoo(src_t&&);
};
}

And then 'Create implementation' for foo() then I get:

namespace a
{
template<typename data_t>
class b
{
public:
void foo();
template<typename src_t>
void makeFoo(src_t&&);
};

template<typename data_t>
void a::b<data_t>::foo()
{

}

}
where 'a::' after void is surplus and I have to delete it manuall to make code look good.

If I 'create implementation' for makeFoo then the created method looks:

template<typename src_t>
void a::b::makeFoo(src_t&&)
{

}
It has only 'inner' template definition of the method and misses 'external' class template.

feline
Whole Tomato Software

United Kingdom
18755 Posts

Posted - Apr 21 2016 : 12:41:51 PM

Thank you for the clear code, I am seeing the same effects here.

For the "foo" function, with the namespace being added, this is a known bug:

case=4240

Since this code still compiles, this is not a high priority bug, but I agree, it does not look as nice as it could, and this is a bug.

For the "makeFoo" template function, this is also a known bug, and it is one we are hoping to get to fairly soon:

case=5476

Unfortunately I don't currently have an estimate, but since this is generating invalid code it is clearly important.

zen is the art of being at one with the two'ness

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